Question on: JAMB Mathematics - 2008
Evaluate \(\int^{\frac{\pi}{2}} _{\frac{-\pi}{2}} cos x dx\)
A
zero
B
1
C
2
D
3
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Correct Option: C
\(\int^{\frac{\pi}{2}} _{\frac{-\pi}{2}} cos x dx = [sinx]^{\frac{\pi}{2}} _{\frac{-\pi}{2}}\\
=sin\frac{\pi}{2} - sin\frac{-\pi}{2}\)
= sin90 – sin-90
= sin90 – sin270
= 1 – (-1)
= 1+1
= 2
= sin90 – sin-90
= sin90 – sin270
= 1 – (-1)
= 1+1
= 2
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