Evaluate log 10 25 log 10 32 - log 10 8 - WAEC Mathematics 1992 Question
Evaluate \(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
A
0.2
B
2
C
100
D
409
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Correct Option: B
\(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
= \(\log_{10} (\frac{25 \times 32}{8})\)
= \(\log_{10} 100 \)
= 2
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