Question on: JAMB Mathematics - 1998
Evaluate ∫(^{\pi}_{2})(sec2 x - tan2x)dx
A
\(\frac{\pi}{2}\)
B
\(\pi\) - 2
C
\(\frac{\pi}{3}\)
D
\(\pi\) + 2
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Correct Option: B
∫(^{\pi}_{2})(sec2 x - tan2x)dx
∫(^{\pi}{2}) dx = [X](^{\pi}{2})
= (\pi) - 2 + c
when c is an arbitrary constant of integration
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