Evaluate pi 2 sec2 x - tan2x dx - JAMB Mathematics 1998 Question
Evaluate ∫
A
B
C
D
correct option: b
∫(^{\pi}_{2})(sec2 x - tan2x)dx
∫(^{\pi}{2}) dx = [X](^{\pi}{2})
= (\pi) - 2 + c
when c is an arbitrary constant of integration
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