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Question on: JSS2 Mathematics - Algebraic Expressions

Expand (π‘₯+2)(π‘₯+3)

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(π‘₯+2)(π‘₯+3)=π‘₯β‹…π‘₯+π‘₯β‹…3+2β‹…π‘₯+2β‹…3

=π‘₯2+3π‘₯+2π‘₯+6

=π‘₯2+5π‘₯+6

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