Home » Classroom » WAEC Mathematics 2013 Question

Express frac 2 x 3 - frac 1 x - 2 as a simple f... - WAEC Mathematics 2013 Question

Express \(\frac{2}{x + 3} - \frac{1}{x - 2}\) as a simple fraction
A
\(\frac{x - 7}{x^2 + x - 6}\)
B
\(\frac{x - 1}{x^2 + x - 6}\)
C
\(\frac{x - 2}{x^2 + x - 6}\)
D
\(\frac{x - 27}{x^2 + x - 6}\)
correct option: a
\(\frac{2}{x + 3} - \frac{1}{x - 2}\) = \(\frac{2(x - 2) - (x - 3)}{(x + 3) (x - 2)}\)

= \(\frac{2x - 4 - x - 3}{x^2 - 2x + 3x - 6}\)

= \(\frac{x -7}{x^2 + x - 6}\)

= \(\frac{x - 7}{x^2 + x - 6}\)
Please share this, thanks:

Add your answer

Notice: Posting irresponsibily can get your account banned!

No responses