Factorise 4a 3 2 - 3a - 2 2 - JAMB Mathematics 2020 Question
Factorise (4a + 3) \(^2\) - (3a - 2)\(^2\)
A
(a + 1)(a + 5)
B
(a - 5)(7a - 1)
C
(a + 5)(7a + 1)
D
a(7a + 1)
correct option: c
The goal of factorization is to breakdown the given number into a simpler one. The result is usually two or more expressions that when multiplied gives the original number.
Recall that a\(^2\) - b\(^2\) = (a + b) (a - b)
Hence,
(4a + 3) \(^2\) - (3a - 2)\(^2\) => (a + b) (a - b)
= ([4a + 3] + [3a - 2])([4a + 3] + [3a - 2])
= (4a + 3 + 3a - 2)(4a + 3 - 3a + 2)
= (7a + 1)(a + 5)
= (a + 5) (7a + 1)
Ans: (a + 5) (7a + 1)
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