Question on: WAEC Mathematics - 2001
Factorize \(6x^2 + 7x - 20\)
A
(6x - 5)(x + 4)
B
2(3x-5)(x+2)
C
(3x+4)(2x-5)
D
(3x-4)(2x+5)
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Correct Option: D
\(6x^2 + 7x - 20\)
= \(6x^2 + 15x - 8x - 20\)
= \(3x(2x + 5) - 4(2x + 5)\)
= \((3x - 4)(2x + 5)\)
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