Factorize completely ac - 2bc - a 4b2 - JAMB Mathematics 2004 Question
Factorize completely ac - 2bc - a + 4b2
A
(a - 2b)(c - a - 2b)
B
(a - 2b)(c + a +2b)
C
(a - 2b)(c - a + 2b)
D
(a - 2b)(c + a - 2b)
correct option: a
ac - 2bc - a2 + 4b2
ac - 2bc - (a2 - 4b2)
ac - 2bc - (a2 -(2b)2)
c(a - 2b) - {(a - 2b)(a + 2b)}
(a - 2b)(c - (a + 2b))
(a - 2b)(c - a - 2b)
ac - 2bc - (a2 - 4b2)
ac - 2bc - (a2 -(2b)2)
c(a - 2b) - {(a - 2b)(a + 2b)}
(a - 2b)(c - (a + 2b))
(a - 2b)(c - a - 2b)
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