Factorize completely frac x 3 3x 2 - 10x 2x 2 -... - JAMB Mathematics 2010 Question
Factorize completely \(\frac{x^3 + 3x^2 - 10x}{2x^2 - 8}\)
A
\(\frac{x(x - 5)}{2(x + 2)}\)
B
\(\frac{x(x + 5)}{2(x + 2)}\)
C
\(\frac{x(x - 5)}{2(x - 2)}\)
D
\(\frac{x ^2 + 5}{2x + 4}\)
correct option: b
\(\frac{x^3 + 3x^2 - 10x}{2x^2 - 8}\) = \(\frac {x(x^2 + 3x - 10)}{2(x^2 - 4)}\)
= \(\frac {x(x^2 + 5x - 2x - 10)}{2(x + 2)(x - 2)}\)
= \(\frac {x(x - 2)(x + 5)}{2(x + 2)(x - 2)}\)
= \(\frac {x(x + 5)}{2(x + 2)}\)
= \(\frac {x(x^2 + 5x - 2x - 10)}{2(x + 2)(x - 2)}\)
= \(\frac {x(x - 2)(x + 5)}{2(x + 2)(x - 2)}\)
= \(\frac {x(x + 5)}{2(x + 2)}\)
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