Question on: JAMB Mathematics - 2010
Factorize completely (\frac{x^3 + 3x^2 - 10x}{2x^2 - 8})
A
\(\frac{x(x - 5)}{2(x + 2)}\)
B
\(\frac{x(x + 5)}{2(x + 2)}\)
C
\(\frac{x(x - 5)}{2(x - 2)}\)
D
\(\frac{x ^2 + 5}{2x + 4}\)
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Correct Option: B
(\frac{x^3 + 3x^2 - 10x}{2x^2 - 8}) = (\frac {x(x^2 + 3x - 10)}{2(x^2 - 4)})
= (\frac {x(x^2 + 5x - 2x - 10)}{2(x + 2)(x - 2)})
= (\frac {x(x - 2)(x + 5)}{2(x + 2)(x - 2)})
= (\frac {x(x + 5)}{2(x + 2)})
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