Question on: JAMB Mathematics - 2020
Find all real number x which satisfy the inequality \(\frac{1}{3}\) (x + 1) - 1 > \(\frac{1}{5}\)(x + 4)Â
x < 11
x < -1
x > 6
x > 11
What we need is a solution set that satisfies the given inequality. Each value in the solution set will satisfy the inequality and no other value will satisfy the inequality.
\(\frac{1}{3}\) (x + 1) - 1 > \(\frac{1}{5}\)(x + 4)Â = \(\frac{x + 1}{3} - 1\) > \(\frac{x + 4}{5}\)Â
\(\frac{x +Â 1}{3} - \frac{x + 4}{5} -1\) > 0Â
= \(\frac{5x + 5 - 3x - 12}{15}\)Â
2x - 7 > 15
2x > 22
Divide through by 2:
x > 11
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