Question on: JAMB Mathematics - 2008
A
12.5cm2
B
75.0cm2
C
78.5cm2
D
84.8cm2
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Correct Option: D
Area of semicircle + Area of rectangle
A = \(\frac{1}{2} \pi r^2\) + LB
A = \(\frac{1}{2} \times \frac{22}{77} \times (\frac{5}{2})^2 + (15 \times 5)\)
= \(\frac{1}{2}\times \frac{22}{7} \times \frac{25}{4} + 75\)
A = \(\frac{275}{28} + \frac{75}{1}\)
\(\frac{275 + 2100}{28} = \frac{2375}{28}\)
A = 84.8cm2
A = \(\frac{1}{2} \pi r^2\) + LB
A = \(\frac{1}{2} \times \frac{22}{77} \times (\frac{5}{2})^2 + (15 \times 5)\)
= \(\frac{1}{2}\times \frac{22}{7} \times \frac{25}{4} + 75\)
A = \(\frac{275}{28} + \frac{75}{1}\)
\(\frac{275 + 2100}{28} = \frac{2375}{28}\)
A = 84.8cm2
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