Question on: JAMB Mathematics - 2008

Area of semicircle + Area of rectangle

A = (\frac{1}{2} \pi r^2) + LB

A = (\frac{1}{2} \times \frac{22}{77} \times (\frac{5}{2})^2 + (15 \times 5))

= (\frac{1}{2}\times \frac{22}{7} \times \frac{25}{4} + 75)

A = (\frac{275}{28} + \frac{75}{1})

(\frac{275 + 2100}{28} = \frac{2375}{28})

A = 84.8cm²