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Find the curved surface area of the frustrum in... - JAMB Mathematics 1990 Question

Find the curved surface area of the frustrum in the figure
A
16\(\pi \sqrt{10}\)cm2
B
20\(\pi \sqrt{10}\)cm2
C
24\(\pi \sqrt{10}\)cm2
D
36\(\pi \sqrt{10}\)cm2
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Correct Option: B

(\frac{x}{4} = \frac{6 + x}{6})

6x = 4(6 + x) = 24 + 4x

x = 12 = c = (\pi RL - \pi L)

= (\pi (6) \sqrt{18^2} + 6^2 - \pi \times 4 \times \sqrt{12^2} + 4^2)

= 6(\pi \sqrt{360} - 4 \pi \sqrt{160})

= 36(\pi \sqrt{10} - 16 \pi \sqrt{10})

= 20(\pi \sqrt{10})cm2

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