Find the equation of a line perpendicular to li... - JAMB Mathematics 2011 Question

2y = 5x + 4 (4, 2)

y = (\frac{5x}{2}) + 4 comparing with

y = mx + e

m = (\frac{5}{2})

Since they are perpendicular

m₁m₂ = -1

m₂ = (\frac{-1}{m_1}) = -1

(\frac{5}{2}) = -1 x (\frac{2}{5})

The equator of the line is thus

y = mn + c (4, 2)

2 = -(\frac{2}{5})(4) + c

(\frac{2}{1}) + (\frac{8}{5}) = c

c = (\frac{18}{5})

(\frac{10 + 5}{5}) = c

y = -(\frac{2}{5})x + (\frac{18}{5})

5y = -2x + 18

or 5y + 2x - 18 = 0