Home » Classroom » JAMB Mathematics 2005 Question

Find the equation of the perpendicular at the p... - JAMB Mathematics 2005 Question

Find the equation of the perpendicular at the point (4,3) to the line y + 2x = 5

A
2y - x = 4
B
y + 2x = 3
C
y + 2x = 5
D
2y - x = 2
Ask EduPadi AI...
Correct Option: D

Gradient of the line y + 2x = 5 = -2

Gradient of the line perpendicular to

y + 2x + 5 = 1/2

equation of a line perpendicular to

y + 2x = 5 at the point (4, 3)

y - y1 = m(x - x1)

y - 3 = 1/2(x - 4)

2y - 6 = x -4

2y - x = 2

Please share this, thanks:

#JAMB #JAMB

Add your answer

Notice: Please post responsibly.

No responses