Question on: JAMB Mathematics - 2018
Find the equation of the tangent at the point (2, 0) to the curve y = x\(^2\) - 2x
A
y = 2x - 4
B
y = 2x + 4
C
y = 2x - 2
D
y = 2x + 2
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Correct Option: A
To find the gradient to the curve, we differentiate the equation of the curve with respect to x
 \(\frac{dy}{dx}\) 2x - 2
 The gradient of the curve is the same with that of the tangent.
 At point (2, 0) \(\frac{dy}{dx}\) = 2(2) - 2
 = 4 – 2 = 2
 The equation of the tangent is given by (y - y1) \(\frac{dy}{dx}\) (x – x1)
 At point (x1, y1) = (2, 0)
 y - 0 = 2(x - 2)
 y = 2x - 4
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