Question on: JAMB Mathematics - 2008
Find the gradient of a line which is perpendicular to the line with the equation 3x + 2y + 1 = 0
A
3/2
B
2/3
C
-2/3
D
-3/2
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Correct Option: B
3X + 2Y + 1 = 0
2Y = -3X - 1
\(\frac{-3}{2}X - \frac{1}{2}\)
Gradient of 3X + 2Y +1 = 0 is -3/2
Gradient of a line perpendicular to 3X + 2Y + 1 = 0
\(=-1 \div \frac{3}{2}\\ =-1 \times \frac{-2}{3}=\frac{2}{3}\)
2Y = -3X - 1
\(\frac{-3}{2}X - \frac{1}{2}\)
Gradient of 3X + 2Y +1 = 0 is -3/2
Gradient of a line perpendicular to 3X + 2Y + 1 = 0
\(=-1 \div \frac{3}{2}\\ =-1 \times \frac{-2}{3}=\frac{2}{3}\)
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