Question on: JAMB Mathematics - 1999

find the length XZ in the triangle
A
\(\sqrt{7m}\)
B
\(\sqrt{6m}\)
C
\(\sqrt{5m}\)
D
\(\sqrt{3m}\)
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Correct Option: A

xz2 = xy2 + yx2 - 2(xy) (yz) cos 120o

= 22 + 12 - 2(2) (1) cos 1202

= 4 + 1 - 4x - cos 60 = 5 - 4x - (\frac{1}{2})

5 + 2 = 7

xz = (\sqrt{7})m

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