Find the mean of the distribution above - JAMB Mathematics 2003 Question
A
1
B
2
C
3
D
4
correct option: c
(Mean = \frac{(0 \times 1) + (1 \times 2) + (2 \times 2) + (3 \times 1) + (4 \times 9)}{1 + 2 + 2 + 1 + 9}=\frac{(0 + 2 + 4 + 3 + 36)}{15}=\frac{45}{15}=3)
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