Question on: JAMB Mathematics - 2014
Find the minimum value of y = x2 - 2x - 3
A
4
B
1
C
-1
D
-4
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Correct Option: D
y = x2 - 2x - 3,
Then \(\frac{\delta y}{\delta x} = 2x - 2\)
But at minimum point,\(\frac{\delta y}{\delta x} = 0\),
Which means 2x - 2 = 0
2x = 2
x = 1.
Hence the minimum value of y = x2 - 2x - 3 is;
ymin = (1)2 - 2(1) - 3
ymin = 1 - 2 - 3
ymin = -4
Then \(\frac{\delta y}{\delta x} = 2x - 2\)
But at minimum point,\(\frac{\delta y}{\delta x} = 0\),
Which means 2x - 2 = 0
2x = 2
x = 1.
Hence the minimum value of y = x2 - 2x - 3 is;
ymin = (1)2 - 2(1) - 3
ymin = 1 - 2 - 3
ymin = -4
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