Question on: WAEC Mathematics - 2002
Find the nth term of the sequence 4, 10, 16 ,...
A
2(3n- 1)
B
2(2 + 3 n-1)
C
2 n + 2
D
2(3n+2)
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Correct Option: A
\(T_{1} = 4; T_2 = 10; T_3 = 16\)
\(T_{2} - T_1 = T_3 - T_1 = 6\)
\(T_n = a + (n - 1) d\)
= \(4 + (n - 1) \times 6\)
= \(4 + 6n - 6\)
= \(6n - 2\)
= 2(3n - 1)
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