Question on: JAMB Mathematics - 1991

Find the range of values of x which satisfy the inequality (\frac{x}{2}) + (\frac{x}{3}) + (\frac{x}{4}) < 1

A
x < \(\frac{12}{13}\)
B
x < 13
C
x < 9
D
\(\frac{13}{12}\)
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Correct Option: A

(\frac{x}{2}) + (\frac{x}{3}) + (\frac{x}{4})< 1

= (\frac{6x + 4x + 3x < 12}{12})

i.e. 13 x < 12 = x < (\frac{12}{13})

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