Find the size of the angle marked x in the diag... - WAEC Mathematics 2011 Question

x + 52^o = 90

x = 90 - 52

x = 38^o

k = opposite angle Z

k = 38^o

y + k = 90^o

y + 38^o = 90^o

y = 90^o - 38^o

y = 52^o

y = x = 180^o(sum of angles on straight line)

52 + x = 180^o

x = 180 - 52

x = 128