Question on: JAMB Mathematics - 1998
Find the value of k if (\frac{k}{\sqrt{3} + \sqrt{2}}) = k(\sqrt{3 - 2})
A
3
B
2
C
\(\sqrt{3}\)
D
\(\sqrt 2\)
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Correct Option: D
(\frac{k}{\sqrt{3} + \sqrt{2}}) = k(\sqrt{3 - 2})
(\frac{k}{\sqrt{3} + \sqrt{2}}) x (\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}})
= k(\sqrt{3 - 2})
= k((\sqrt{3} - \sqrt{2}))
= k(\sqrt{3 - 2})
= k(\sqrt{3}) - k(\sqrt{2})
= k(\sqrt{3 - 2})
k2 = (\sqrt{2})
k = (\frac{2}{\sqrt{2}})
= (\sqrt{2})
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