Question on: WAEC Mathematics - 2004

The sum of angles at point = 360^o
(x+10)^o + (4x+50)^o + 20^o + 3x^o + 2x^o = 360^o
10x + 80^o = 360^o
10x = 360^o - 80^o = 280^o
(\frac{280}{10}=28^{\circ})