Find the value of x in the figure above - JAMB Mathematics 2014 Question

In the figure above, (\frac{x}{\sin 60^o} = \frac{10}{\sin 30^o}) (Sine rule)

x = (\frac{10 \sin 60^o}{\sin 30^o})

= 10 x (\frac{\sqrt{3}}{2} \times \frac{1}{2})

= 10 x (\frac{\sqrt{3}}{2} \times \frac{2}{1})

= 10(\sqrt{3})cm