Find the value of x in the figure above - JAMB Mathematics 2014 Question
A
20\(\sqrt{3}\)cm
B
10\(\sqrt{3}\)cm
C
5\(\sqrt{3}\)cm
D
4\(\sqrt{3}\)cm
correct option: b
In the figure above, \(\frac{x}{\sin 60^o} = \frac{10}{\sin 30^o}\) (Sine rule)
x = \(\frac{10 \sin 60^o}{\sin 30^o}\)
= 10 x \(\frac{\sqrt{3}}{2} \times \frac{1}{2}\)
= 10 x \(\frac{\sqrt{3}}{2} \times \frac{2}{1}\)
= 10\(\sqrt{3}\)cm
x = \(\frac{10 \sin 60^o}{\sin 30^o}\)
= 10 x \(\frac{\sqrt{3}}{2} \times \frac{1}{2}\)
= 10 x \(\frac{\sqrt{3}}{2} \times \frac{2}{1}\)
= 10\(\sqrt{3}\)cm
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