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Find the values of k in the equation 6k2 5k 6 - WAEC Mathematics 2013 Question

Find the values of k in the equation 6k2 = 5k + 6

A
{\(\frac{-2}{3}, \frac{-3}{2}\)}
B
{\(\frac{-2}{3}, \frac{3}{2}\)}
C
{\(\frac{2}{3}, \frac{-3}{2}\)}
D
{\(\frac{2}{3}, \frac{3}{2}\)}
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Correct Option: B

6k2 = 5k + 6

6k2 - 5k - 6 = 0

6k2 - 0k + 4k - 6 = 0

3k(2k - 3) + 2(2k - 3) = 0

(3k + 2)(2k - 3) = 0

3k + 2 = 0 or 2k - 3 = 0

3k = -2 or 2k = 3

k = (\frac{-2}{3}) or k = (\frac{3}{2})

k = ((\frac{-2}{3}), k = (\frac{3}{2}))

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