For the reaction 2A 3B 4C the equilibrium const... - SS3 Chemistry Chemical Equilibrium Question
For the reaction: 2A + 3B ⇌ 4C, the equilibrium constant (Kc) expression is:
A
Kc = [C]4 / ([A]2 X [B]3)
B
Kc = [C]2 / ([A]3 X [B]4)
C
Kc = [A]2 / ([B]3 X [C]4)
D
Kc = [A]3 / ([B]2 X [C]4)
correct option: a
The equilibrium constant (Kc) expression is obtained by writing the concentrations of products (C) raised to their stoichiometric coefficients in the numerator and the concentrations of reactants (A and B) raised to their respective stoichiometric coefficients in the denominator. In this case, the stoichiometric coefficients of C, A, and B are 4, 2, and 3, respectively, leading to the expression Kc = [C]4 / ([A]2 X [B]3).
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