For the reaction 2A 3B - gt C the rate law is g... - SS2 Chemistry Chemical Kinetics Question
For the reaction: 2A + 3B -> C, the rate law is given by Rate = k [A]2 [B]. If the initial concentrations of A and B are 0.2 M and 0.3 M, respectively, and the rate constant (k) is 0.01 M-2 s-1, what will be the rate of reaction after 10 seconds?
Given: [A]₀ = 0.2 M, [B]₀ = 0.3 M, k = 0.01 M-2 s-1, t = 10 seconds.
Using the rate law, we can calculate the rate of the reaction:
Rate = k [A]2 [B]
Rate = (0.01 M-2 s-1) × (0.2 M)2 × (0.3 M)
Rate = 0.01 M-2 s-1 × 0.04 M2 × 0.3 M
Rate = 0.0012 M/s
So, the rate of the reaction after 10 seconds is 0.0012 M/s.
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