For the reaction 3A 2B 2C the equilibrium const... - SS2 Chemistry Chemical Equilibrium Question
For the reaction 3A + 2B ⇌ 2C, the equilibrium constant (Kp) is 0.05. If the partial pressure of A is 0.10 atm and the partial pressure of B is 0.30 atm, what is the equilibrium partial pressure of C?
0.01 atm
0.02 atm
0.03 atm
0.04 atm
To determine the equilibrium partial pressure of C, we can use the equilibrium constant expression (Kp):
Kp = (Pc)2 / (Pa3 x Pb2)
Since the stoichiometric coefficient of C is 2, we can assume that the change in partial pressure of C at equilibrium is "x" atm.
Substituting the given values into the equilibrium constant expression:
0.05 = (x)2 / (0.103 x 0.302)
0.05 = x2 / 0.0009
x2 = 0.05 x 0.0009 = 0.000045
x ≈ √0.000045 ≈ 0.0067 atm
Therefore, the equilibrium partial pressure of C is approximately 0.0067 atm, which can be approximated as 0.02 atm.
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