Question on: JAMB Mathematics - 2024
\(\frac{d}{dx} [\log (4x^3 - 2x)]\) is equal to:
A
\(\frac{12x - 2}{4x^2}\)
B
\(\frac{43x^2 - 2x}{7x}\)
C
\(\frac{4x^2 - 2}{7x + 6}\)
D
\(\frac{12x^2 - 2}{4x^3 - 2x}\)
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Correct Option: D
Derivative using the chain rule:
1. Let u = 4x³ - 2x
2. du/dx = 12x² - 2
3. d/dx [log(u)] = 1/u x du/dx = (12x² - 2) / (4x³ - 2x)
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