From the top of a vertical mast 150m high two h... - JAMB Mathematics 1998 Question

From the top of a vertical mast 150m high., two huts on the same ground level are observed. One due east and the other due west of the mast. Their angles of depression are 60^o and 45^o respectively. Find the distance between the huts

150(1 +

\sqrt{3}

50(

\sqrt{3}

\sqrt{3}

150

\sqrt{3}

\frac{50}{\sqrt{3}}

correct option: b

(\frac{150}{Z}) = tan 60^o,

Z = (\frac{150}{tan 60^o})

= (\frac{150}{3})

= 50(\sqrt{3})cm

(\frac{150}{X x Z}) = tan45^o = 1

X + Z = 150

X = 150 - Z

= 150 - 50(\sqrt{3})

= 50( (\sqrt{3}) - (\sqrt{3}))m

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