Question on: JAMB Mathematics - 1998
From the top of a vertical mast 150m high., two huts on the same ground level are observed. One due east and the other due west of the mast. Their angles of depression are 60o and 45o respectively. Find the distance between the huts
A
150(1 + \(\sqrt{3}\))m
B
50( \(\sqrt{3}\) - \(\sqrt{3}\))m
C
150 \(\sqrt{3}\)m
D
\(\frac{50}{\sqrt{3}}\)m
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Correct Option: B
(\frac{150}{Z}) = tan 60o,
Z = (\frac{150}{tan 60^o})
= (\frac{150}{3})
= 50(\sqrt{3})cm
(\frac{150}{X x Z}) = tan45o = 1
X + Z = 150
X = 150 - Z
= 150 - 50(\sqrt{3})
= 50( (\sqrt{3}) - (\sqrt{3}))m
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