Question on: JAMB Mathematics - 2022
Given sec\(^2\)θ + tan\(^2\)θ = 3, find the angle θ
A
90º
B
30º
C
45º
D
60º
Ask EduPadi AI for a detailed answer
Correct Option: C
sec\(^2\)θ + tan\(^2\)θ = 3
sec\(^2\)θ = 1 + tan\(^2\)θ
: Hence,
1 + tan\(^2\)θ + tan\(^2\)θ = 3
2tan\(^2\)θ = 3 - 1
2tan\(^2\)θ = 2
divide through by 2
tan\(^2\)θ = 1
tanθ = √1
tanθ = 1
θ = tan\(^{-1}\) (1)
θ = 45º
Add your answer
Please share this, thanks!
No responses