Question on: JAMB Mathematics - 2019

Given \(\sin 58° = \cos p°\), find p.

A
48°
B
58°
C
32°
D
52°
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Correct Option: C

\(\sin \theta = \cos (90 - \theta)\)

\(\sin \theta = \cos (90 - 58)\)

= \(\cos 32\)

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