Question on: WAEC Mathematics - 2000
Given that \(27^{(1+x)}=9,)\ find x
A
-3
B
\(\frac{-1}{3}\)
C
\(\frac{5}{3}\)
D
2
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Correct Option: B
\(27^{(1+x)}=9\
3^{3(1+x)}=3^2\
3(1+x)=2\
3+3x = 2\
3x = -1
x = \frac{-1}{3}\)
3^{3(1+x)}=3^2\
3(1+x)=2\
3+3x = 2\
3x = -1
x = \frac{-1}{3}\)
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