Given that 81 times 2 2n-2 K find sqrt K - WAEC Mathematics 1999 Question
Given that \(81\times 2^{2n-2} = K, find \sqrt{K}\)
A
\(4.5\times 2^{n}\)
B
\(4.5\times 2^{2n}\)
C
\(9\times 2^{n-1}\)
D
\(9\times 2^{2n}\)
correct option: c
\(K = 81 \times 2^{2n - 2}\)
\(\sqrt{K} = \sqrt{81 \times 2^{2n - 2}}\)
= \(9 \times 2^{n - 1}\)
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