Question on: WAEC Chemistry - 1989
Given that for the reaction. N2(g) + 3H2(g) ⇌ 2NH3(g) ∆H = -92kJ. What is the enthalpy of formation of ammonia from its elements?
A
-46KJ mol -1
B
-184KJmol -1
C
-92KJmol -1
D
184KJmol -1
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Correct Option: A
In the reaction the enthalpy of formation 2 mole of NH3 is - 92kJ. Therefore the standard \(\Delta H\) of formation = \(\frac{-92kJ}{2} = -46KJmol^{-1}\).
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