Question on: WAEC Mathematics - 1997
Given that \(\frac{1}{2} \log_{10} P = 1\), find the value of P.
A
104
B
103
C
102
D
101
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Correct Option: C
\(\frac{1}{2} \log_{10} P = 1\)
\(\log_{10} P^{\frac{1}{2}} = 1\)
\(P^{\frac{1}{2}} = 10^{1}\)
\(\implies P = 10^{2}\)
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