Question on: JAMB Mathematics - 2010
Given that log 2 = 0.3010, log 7 = 0.8451. Evaluate log 112.
A
2.1461
B
2.0491
C
3.1461
D
2.5441
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Correct Option: B
log 112 = log(16 x 7)
= log 16 + log7
= log 24 + log7
= 4log2 + log7
= 4(0.3010) + 0.8451
= 1.204 + 0.8451
= 2.0491
= log 16 + log7
= log 24 + log7
= 4log2 + log7
= 4(0.3010) + 0.8451
= 1.204 + 0.8451
= 2.0491
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