Given that log4 Y - 1 log4 frac 1 2 x 1 and log... - JAMB Mathematics 1998 Question

log₄(y - 1) + log₄((\frac{1}{2})x) = 1

log₄(y - 1)((\frac{1}{2})x) (\to) (y - 1)((\frac{1}{2})x) = 4 ........(1)

log₂(y + 1) + log₂x = 2

log₂(y + 1)x = 2 (\to) (y + 1)x = 2₂ = 4.....(ii)

From equation (ii) x = (\frac{4}{y + 1})........(iii)

put equation (iii) in (i) = y (y - 1)[(\frac{1}{2}(\frac{4}{y - 1}))] = 4

= 2y - 2

= 4y + 4

2y = -6

y = -3

x = (\frac{4}{-3 + 1})

= (\frac{4}{-2})

X = 2

therefore x = -2, y = -3