Given that m -3 and n 2 find the value of frac ... - WAEC Mathematics 1999 Question
Given that m = -3 and n = 2 find the value of \(\frac{3n^2 - 2m^3}{m}\)
A
-22
B
-14
C
14
D
22
correct option: a
Given that m = -3, n = 2, the value of
\(\frac{3n^2 - 2n^3}{m}\
\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22\)
\(\frac{3n^2 - 2n^3}{m}\
\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22\)
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