Question on: WAEC Mathematics - 1999
Given that m = -3 and n = 2 find the value of (\frac{3n^2 - 2m^3}{m})
A
-22
B
-14
C
14
D
22
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Correct Option: A
Given that m = -3, n = 2, the value of
(\frac{3n^2 - 2n^3}{m}<br />
\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22)
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