Question on: WAEC Mathematics - 2013
Given that p(\frac{1}{3}) = (\frac{3\sqrt{q}}{r}), make q the subject of the equation
A
q = p\(\sqrt{r}\)
B
q = p3r
C
q = pr3
D
q = pr\(\frac{1}{3}\)
Ask EduPadi AI for a detailed answer
Correct Option: D
p(\frac{1}{3}) = (\frac{3\sqrt{q}}{r})(cross multiply)
3(\sqrt{q}) = r x 3(\frac{\sqrt{q}}{r})(cross multiply)
3(\sqrt{q}) = r x 3(\sqrt{p}) cube root both side
q = 3(\sqrt{r}) x p
q = r(\frac{1}{3})p = pr(\frac{1}{3})
Add your answer
Please share this, thanks!
No responses