Question on: WAEC Mathematics - 2004
Given that (P\propto \frac{1}{\sqrt{r}}) and p = 3 when r = 16, find the value of r when p =-5
A
48
B
64
C
72
D
324
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Correct Option: B
(P \propto \frac{1}{\sqrt{r}} P=3\hspace{1mm}r=16<br /> P = \frac{k}{\sqrt{r}}\Rightarrow 3 = \frac{k}{\sqrt{16}}\Rightarrow \frac{3}{1} = \frac{k}{4} \ \Rightarrow K = 12 \Rightarrow K = 12; P\sqrt{r} = k \Rightarrow \sqrt{r} = \frac{k}{p}<br /> r = \frac{(k)^2}{P}=12^2 \div \frac{3}{2}=\left(\frac{12}{1}\times \frac{2}{3}\right)=8^2<br /> r = 64)
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