Question on: WAEC Mathematics - 2008
Given that x = 2 and y = -(\frac{1}{4}), evaluate (\frac{x^2y - 2xy}{5})
A
zero
B
\(\frac{1}{5}\)
C
1
D
2
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Correct Option: A
Given; x = 2; y = (\frac{-1}{4})
= (\frac{x^2y - 2xy}{5})
= (\frac{2^2(\frac{-1}{4}) - 2(2)(\frac{-1}{4})}{5})
= (\frac{4(\frac{-1}{4}) + 4(\frac{-1}{4})}{5})
= (\frac{1 + 1}{5})
= (\frac{0}{5})
= 0
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