Home » Classroom » JAMB Physics 2004 Question

Given three capacitors 0 3 F 0 5 F and 0 2 F th... - JAMB Physics 2004 Question

Given three capacitors 0.3μF, 0.5μF and 0.2μF, the joint capacitance when arranged to give minimum capacitance is
A
0.1μF
B
0.3μF
C
1.0μF
D
0.5μF
correct option: a

1/C = 1/0.3 + 1/0.5 + 1/0.2 = 10.3333

=> C = 1 / 10.3333 = 0.09677

≅ 0.1μF

∴ C = 0.1μF

Please share this, thanks:

#JAMB #JAMB

Add your answer

Notice: Please post responsibly.

No responses