Question on: JAMB Physics - 2004
Given three capacitors 0.3μF, 0.5μF and 0.2μF, the joint capacitance when arranged to give minimum capacitance is
A
0.1μF
B
0.3μF
C
1.0μF
D
0.5μF
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Correct Option: A
1/C = 1/0.3 + 1/0.5 + 1/0.2 = 10.3333
=> C = 1 / 10.3333 = 0.09677
≅ 0.1μF
∴ C = 0.1μF
=> C = 1 / 10.3333 = 0.09677
≅ 0.1μF
∴ C = 0.1μF
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