Question on: JAMB Chemistry - 2005
How many moles of limestone will be required to produce 5.6g of CaO?
[Ca = 40, C = 12, O= 16]
A
0.20 mol
B
0.10 mol
C
1.12 mol
D
0.56 mol
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Correct Option: B
CaCO3 → CaO + CO2
CaCO3 = 40 + 12 + 16 * 3 = 100, CaO = 40 + 16 = 56
56gt of CaO was produced by 100g of CaCO3
∴ 5.6g of CaO will produce by
(5.6 * 100)/56 = 10g of CaCO3
moles = mass/molar mass = 10/100 = 0.10m
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