How much net work is required to accelerate a 1... - JAMB Physics 2023 Question
How much net work is required to accelerate a 1200 kg car from 10\(ms^{-1}\) to 15\(ms^{-1}\)
A
1.95×\(10^5 j\)
B
1.35×\(10^4 j\)
C
7.5×\(10^4 j\)
D
6.0×\(10^4 j\)
correct option: c
The work done (\(W\)) in accelerating an object is given by the formula:
\[ W = \frac{1}{2} m (v_f^2 - v_i^2) \]
where:
\( m \) is the mass of the object,
\( v_f \) is the final velocity,
\( v_i \) is the initial velocity.
Given:
\( m = 1200 \, \text{kg} \),
\( v_i = 10 \, \text{m/s} \),
\( v_f = 15 \, \text{m/s} \).
\[ W = \frac{1}{2} \times 1200 \times (15^2 - 10^2) \]
\[ W = \frac{1}{2} \times 1200 \times (225 - 100) \]
\[ W = \frac{1}{2} \times 1200 \times 125 \]
\[ W = 75000 \, \text{Joules} \]
Therefore, the correct option is:
\(7.5 \times 10^4 \, \text{J}\)
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