Question on: JAMB Mathematics - 1992
Ice forms on a refrigerator ice-box at the rate of (4 - 06t)g per minute after t minutes. If initially there are 2g of ice in the box, find the mass of ice formed in 5 minutes
A
19.5
B
17.0
C
14.5
D
12.5
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Correct Option: C
\(\frac{dm}{dt}\) = 4 - 0.6t
\(\int\)dm = \(\int\)(4 - 0.6t)dt
m = 4t - 0.3t2 + c, when t = 0, m = 2g
∴ c = 2
m = 4t - 0.3t2 + 2, when t = 5 minutes
m = 4(5) - 0.3(5)2 + 2 = 20 - 7.5
= 14.5
\(\int\)dm = \(\int\)(4 - 0.6t)dt
m = 4t - 0.3t2 + c, when t = 0, m = 2g
∴ c = 2
m = 4t - 0.3t2 + 2, when t = 5 minutes
m = 4(5) - 0.3(5)2 + 2 = 20 - 7.5
= 14.5
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