If 2 log x 3 frac 3 8 6 find the value of x - WAEC Mathematics 2013 Question

2 log x (3(\frac{3}{8})) = 6(divide both sides by 2)

(\frac{2 log_x(3 \frac{3}{8})}{2} = \frac{6}{2})

(\log_x \frac{27}{8} = 3)

(\frac{27}{8} = x^3)

(x^3 = \frac{27}{8})

x = (\sqrt{\frac{27}{8}})

= ((\frac{27}{8}))^{(\frac{1}{3})}

= (\frac{(3^3)^{\frac{1}{3}}}{(2^3)^{\frac{1}{3}}})

= (\frac{3}{2})