Question on: JAMB Mathematics - 2005
If 3214 is divided by 234 and leaves a remainder r, what is the value of r?
A
zero
B
1
C
2
D
3
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Correct Option: C
(\frac{321_4}{23_4}=\frac{(3\times4^{2})+(2\times4^{1})+(1\times4^{0})}{(2\times4^{0})+(3\times4^{0})}=\frac{3\times16+2\times4+1\times1}{2\times4+3\times1}=\frac{48+8+1}{8+3}=\frac{57}{11}=5\hspace{1mm}remainder\hspace{1mm}2\∴r=2_{10} \ Now\hspace{1mm}convert\hspace{1mm}2_{10} \hspace{1mm}to\hspace{1mm}base\hspace{1mm}4\frac{4}{2} = 2\frac{4}{0}=0\hspace{1mm}or\hspace{1mm}2\∴r=2)
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