Question on: WAEC Mathematics - 2007
If \(8^{x+1}=\frac{1}{4}\), find x
A
\(-\frac{5}{3}\)
B
-1
C
\(-\frac{1}{3}\)
D
\(\frac{1}{3}\)
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Correct Option: A
\(8^{x+1}=\frac{1}{4}\
2^{3(x+1)}=2^{-2}\Rightarrow 3(x+1)=-2\Rightarrow 3x+3=-2\
3x=-5\Rightarrow x=\frac{5}{3}\)
2^{3(x+1)}=2^{-2}\Rightarrow 3(x+1)=-2\Rightarrow 3x+3=-2\
3x=-5\Rightarrow x=\frac{5}{3}\)
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